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Status Not under consideration
Workspace IBM i
Categories Db2 for i
Created by Guest
Created on May 4, 2022

RELATED IDEAS

Support subselect and subquery in the SQL join-condition

Please provide an extended JOIN syntax to support EXISTS (subquery) or IN (subquery) in the join condition.


This will facilitate JOINS where NULL values are involved and should be kept.

for example:

with p(rel1id, a1, a2, a3, x) as (
    values
        (1, 'yes', 4, 56, 'blue'),
        (2, 'yes', 4, 56, 'red'),
        (3, 'no', 4, 56, 'white'),
        (4, 'no', 4, NULL, 'green')
),
q(rel2id, a1, a2, a3, y) as (
    values
        (5, 'yes', 4, 56, 'cats'),
        (6, 'no', 4, NULL, 'dog')
)
select p.*, q.rel2id, q.y 
  from p join q on exists (values (p.a1, p.a2, p.a3) 
                           intersect 
                           values (q.a1, q.a2, q.a3))
;

Expected Result:

REL1ID

A1

A2

A3

X

REL2ID

Y

1

yes

4

56

blue

5

cats

2

yes

4

56

red

5

cats

4

no

4


green

6

dog



Idea priority Medium
  • Guest
    Reply
    |     Jun 3, 2022
    IBM does not intend to provide a solution to this request at this time, so it is being closed.

    While we agree this could be a useful addition to SQL, the database team has many higher priority items to work on right now. This request is unlikely to be implemented in the next several years.

    Although we are declining the request, we are keeping it on an internal list so we can reconsider it in the future.
  • Guest
    Reply
    |     May 11, 2022

    This case could be solved by using "is not distinct from".

    with p(rel1id, a1, a2, a3, x) as (
        values
            (1, 'yes', 4, 56, 'blue'),
            (2, 'yes', 4, 56, 'red'),
            (3, 'no', 4, 56, 'white'),
            (4, 'no', 4, NULL, 'green')
    ),
    q(rel2id, a1, a2, a3, y) as (
        values
            (5, 'yes', 4, 56, 'cats'),
            (6, 'no', 4, NULL, 'dog')
    )
    select p.*, q.rel2id, q.y 
      from p join q on 
        p.a1 is not distinct from q.a1 and
        p.a2 is not distinct from q.a2 and
        p.a3 is not distinct from q.a3
    ;

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