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Status Not under consideration
Workspace IBM i
Categories Languages - RPG
Created by Guest
Created on Oct 24, 2019

RELATED IDEAS

Allow array index to start from zero instead of 1

See this idea on ideas.ibm.com

I would like to have the possibility to specify that the index of an array starts from zero instead of 1.

Many times I have to code something like this
eval myArray(x+1) = 1234
where x can have the value zero.

If it was possible to specify that the lower bound of myArr is zero then I could code
eval myArray(x) = 1234
giving a "cleaner" code.


Use Case:

dcl-s myArr packed(7:0) dim(100) LOWERBOUND(0);
dcl-s x int(10);

for x = %lowerbound(myArr) to %upperbound(myArr);
myArr(x) = x;
endfor;

x = %lookup(9999 : myArr);

In this example a new keyword LOWERBOUND i defined. The valid values for it are 1 (default) and 0.
The new bifs %lowerbound() and %upperbound() returns zero and 99 in this example.
The existing %elem() wil still return 100.

Of course bifs like %lookup() must return -1 if no match is found in this case .
That equals %lowerbound() - 1


Idea priority Low
  • Guest
    Reply
    |     Apr 17, 2020

    IBM does not intend to provide a solution to this request at this time, so it is being closed.

    This request does not align with the strategy for future investment in the ILE RPG compiler. IBM feels that it would not enhance the maintainability of RPG programs if array indexes did not always have the same origin.

  • Guest
    Reply
    |     Oct 28, 2019

    Thank you very much.

  • Guest
    Reply
    |     Oct 25, 2019

    This RFE is being reopened because as the submitter pointed out, it is not entirely a duplicate of RFE 137563.

  • Guest
    Reply
    |     Oct 25, 2019

    No this is not a duplicate.

    RFE 137553 changes the index to start from zero for ALL arrays in the program.
    Fairly useless IMHO - You can't use it in existing programs.

    This RFE ( 137563 ) changes the index to start from zero for a specific array.
    Thus you can use it in existing programs.

  • Guest
    Reply
    |     Oct 25, 2019

    This is a duplicate of RFE 137553. https://www.ibm.com/developerworks/rfe/execute?use_case=viewRfe&CR_ID=137553.

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